Intersection of Two Linked Lists LeetCode Solution

Problem Statement Intersection of Two Linked Lists LeetCode Solution – We are given the heads of two strongly linked-lists headA and headB. It is also given that the two linked lists may intersect at some point. We are asked to return the node at which they intersect or null if …

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Permutation Sequence LeetCode Solution

Problem Statement Permutation Sequence LeetCode Solution – The set [1, 2, 3, …, n] contains a total of n! unique permutations. By listing and labeling all of the permutations in order, we get the following sequence for n = 3: “123” “132” “213” “231” “312” “321” Given n and k, return the kth permutation sequence. Example Test Case 1: Input: n …

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Search Suggestions System LeetCode Solution

Problem Statement Search Suggestions System LeetCode Solution – You are given an array of strings products and a string searchWord. Design a system that suggests at most three product names from products after each character of searchWord is typed. Suggested products should have a common prefix with searchWord. If there are more than three products with a …

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Rotate Image LeetCode Solution

Problem Statement Rotate Image LeetCode Solution – You are given an n x n 2D matrix representing an image, rotate the image by 90 degrees (clockwise). You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation. Example Test Case 1: Input: …

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Peeking Iterator LeetCode Solution

Problem Statement Peeking Iterator LeetCode Solution – Design an iterator that supports the peek operation on an existing iterator in addition to the hasNext and the next operations. Implement the PeekingIterator class: PeekingIterator(Iterator<int> nums) Initializes the object with the given integer iterator iterator. int next() Returns the next element in the array and moves the pointer to the next element. boolean …

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Defanging an IP Address LeetCode Solution

Problem Statement Defanging an IP Address LeetCode Solution – Given a valid (IPv4) IP address, return a defanged version of that IP address. A defanged IP address replaces every period “.” with “[.]”. Input: address = “1.1.1.1” Output: “1[.]1[.]1[.]1” Explanation The intuition is very simple. 1. create a Stringbuilder str 2. loop through the address string …

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